This is log. 〖1+log〗_2 (х-1)=log_((х-1))⁡4. 02 лог 8 (2x) +log8(x2+1-2x) =43. лог17 7-х -2. log2(7-х)=2log8 3.

This is log. 〖1+log〗_2 (х-1)=log_((х-1))⁡4. 02 лог 8 (2x) +log8(x2+1-2x) =43. лог17 7-х -2. log2(7-х)=2log8 3.
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