Log2 10 log2 5 log2 8. Лог2 х > 1. 〖1+log〗_2 (х-1)=log_((х-1))⁡4. log2 8 3x log2 3+x +1. log3 ( √ x − 1) = 1.

Log2 10 log2 5 log2 8. Лог2 х > 1. 〖1+log〗_2 (х-1)=log_((х-1))⁡4. log2 8 3x log2 3+x +1. log3 ( √ x − 1) = 1.
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